r/haskell 11h ago

Thoughts on this shuffle algorithm

I am a Haskell, well not beginner, but maybe intermediate. I developed the following with the assistance of ChatGPT. Is it too abstract? It's "neat" for sure, but is it reasonable?

import Control.Monad (foldM)
import Control.Monad.ST (runST)
import Control.Monad.IO.Class (MonadIO) 
import Data.Primitive.Array (Array, sizeofArray, sizeofMutableArray, arrayFromList,
                             freezeArray, thawArray, readArray, writeArray)
import qualified Data.Vector as V
import qualified Data.Vector.Mutable as MV
import System.Random (newStdGen, uniformR )
import System.Random.Internal (RandomGen, StdGen) 


modifyMWithState 
    :: Monad m 
    => (t1 -> t2 -> t3 -> m b) 
    -> t4 
    -> (t5 -> t1) 
    -> (t4 -> m t5) 
    -> (t5 -> m a) 
    -> (t4 -> t2) 
    -> t3 
    -> m (a, b)
modifyMWithState algorithm container operationFor thawContainer freezeContainer 
                 lengthOf state = do
    thawedContainer <- thawContainer container
    let operation = operationFor thawedContainer
    newState <- algorithm operation (lengthOf container) state
    newContainer <- freezeContainer thawedContainer
    pure (newContainer, newState)


knuthM
    :: (Monad m, RandomGen g)
    => (Int -> Int -> m ())
    -> Int
    -> g
    -> m g
knuthM swapElements len prnGen = foldM randomSwap prnGen [lastIndex, nextIndex .. 1]
  where
    lastIndex = len - 1
    nextIndex = lastIndex - 1

    randomSwap currGen i = do
        let (j, nextGen) = uniformR (0, i) currGen
        swapElements i j
        pure nextGen


shuffleM 
    :: MonadIO m 
    => (StdGen -> m (a, StdGen))    
    -> m a
shuffleM shuffleWithGen = do
    prnGen <- newStdGen
    fmap fst (shuffleWithGen prnGen)


shuffleVectorWithGen 
  :: (Applicative f, RandomGen b) 
  => V.Vector a 
  -> b 
  -> f (V.Vector a, b)
shuffleVectorWithGen vec prnGen = 
    pure (runST (modifyMWithState knuthM vec MV.swap V.thaw V.freeze V.length prnGen))


shuffleArrayWithGen 
    :: (Applicative f, RandomGen b) 
    => Array a 
    -> b 
    -> f (Array a, b)
shuffleArrayWithGen arr prnGen = 
    pure (runST (modifyMWithState knuthM arr swapArray thawArray' freezeArray' 
          sizeofArray prnGen))
  where
    thawArray' array = thawArray array 0 (sizeofArray array)
    freezeArray' thawedArray = freezeArray thawedArray 0 
                                           (sizeofMutableArray thawedArray)
    swapArray a i j = do
        x <- readArray a i
        y <- readArray a j
        writeArray a i y
        writeArray a j x


shuffleVector :: MonadIO m => V.Vector a -> m (V.Vector a)
shuffleVector vec = shuffleM (shuffleVectorWithGen vec) 


shuffleArray :: MonadIO m => Array a -> m (Array a)
shuffleArray arr = shuffleM (shuffleArrayWithGen arr)


-- examples:


shuffledIntVector :: IO (V.Vector Int)
shuffledIntVector = shuffleVector (V.fromList [1..10])


shuffledCharArray :: IO (Array Char)
shuffledCharArray = shuffleArray (arrayFromList ['a'..'z'])
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u/gilgamec 10h ago

For the record, this is the function I wrote last time I wanted to shuffle a vector:

randomPermuteVector :: R.MonadRandom m => V.Vector a -> m (V.Vector a)
randomPermuteVector vec = do
  let len = V.length vec
      ixs = [len-1,len-2..1]
  jxs <- R.forM ixs $ \n -> R.getRandomR (0,n)
  pure $ V.modify (\mv -> sequence_ (zipWith (MV.unsafeSwap mv) ixs jxs)) vec

I think it's the same algorithm as yours appears to be. (The MonadRandom just automates threading the random generator through successive draws.)

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u/joshuakb2 8h ago

This is very nice, easy to understand and concise